Niro
Gebruiker
- Lid geworden
- 5 jan 2007
- Berichten
- 20
Weet er iemand soms hoe ik in het volgende script een automatische thumbnailscript verwerk?
Ik ben nog een beginner in php. Ik heb al opzoekingen gedaan maar weet niet hoe het hier in te verwerken.
PHP:
if (isset($opslaan)) {
$sql3="INSERT INTO autos(merk, type, bouwjaar, brandstof, verbruik, prijs, carroserietype, vermogen, kleur, opties, transmissie, versnellingen, cilinderinhoud, deuren, km) VALUES('$merk', '$type', '$bouwjaar', '$brandstof', '$verbruik', '$prijs', '$carroserietype', '$vermogen', '$kleur', '$opties', '$transmissie', '$versnellingen', '$cilinderinhoud', '$deuren', '$km')";
mysql_connect("192.168.0.69","cwint","..."); // mysql_connect("plaatsvandatabase","loginaanm","paswoord");
mysql_select_db("geysensm"); // mysql_select_db("naamvandatabase");
$result = mysql_query("$sql3");
$auto_id = mysql_insert_id();
$number_of_file_fields = 0;
$number_of_uploaded_files = 0;
$number_of_moved_files = 0;
$uploaded_files = array();
$upload_directory = dirname(__file__) . '/uploaded/'; //set upload directory
/**
* we get a $_FILES['images'] array ,
* we procee this array while iterating with simple for loop
* you can check this array by print_r($_FILES['images']);
*/
for ($i = 0; $i < count($_FILES['images']['name']); $i++) {
$number_of_file_fields++;
if ($_FILES['images']['name'][$i] != '') { //check if file field empty or not
$number_of_uploaded_files++;
$uploaded_files[] = $_FILES['images']['name'][$i];
if (move_uploaded_file($_FILES['images']['tmp_name'][$i], $upload_directory . $_FILES['images']['name'][$i])) {
$number_of_moved_files++;
$fotos="INSERT INTO images(image, auto_id) VALUES('".$_FILES['images']['name'][$i]."', '$auto_id')";
mysql_connect("192.168.0.69","cwint","..."); // mysql_connect("plaatsvandatabase","loginaanm","paswoord");
mysql_select_db("geysensm"); // mysql_select_db("naamvandatabase");
$result = mysql_query("$fotos");}
}else if(!empty($_FILES['images']['name'])){
$fotosl="INSERT INTO images(image, auto_id) VALUES('geen_afbeelding.jpg', '$auto_id')";
mysql_connect("192.168.0.69","cwint","..."); // mysql_connect("plaatsvandatabase","loginaanm","paswoord");
mysql_select_db("geysensm"); // mysql_select_db("naamvandatabase");
$result = mysql_query("$fotosl");
}
}
echo "Number of File fields created $number_of_file_fields.<br/> ";
echo "Number of files submitted $number_of_uploaded_files . <br/>";
echo "Number of successfully moved files $number_of_moved_files . <br/>";
echo "File Names are <br/>" . implode(',', $uploaded_files);
print "$merk is succesvol toegevoegd!<br /><br />";
}Ik ben nog een beginner in php. Ik heb al opzoekingen gedaan maar weet niet hoe het hier in te verwerken.
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