hallo ik heb een registreer script hij werkt goed alleen het wachtwoordwordt in je data base heel anders dan het ingevulde wachtwoord.
het script:
het script:
PHP:
<?
$database ="@@@@@@";
$server ="@@@@@@@@";
$user ="@@@@@@";
$passw ="@@@@@";
mysql_connect("$server","$user", "$passw");
mysql_select_db($database);
if(!isset($_REQUEST['submit'])){
?>
<form method=post acion="">
<table>
<tr>
<td>
<font face=verdana size=1>gebruikersnaam:
</td>
<td>
<input type="text" name="name" maxlength="15">
</td>
</tr>
<tr>
<td>
<font face=verdana size=1>wachtwoord:
</td>
<td>
<input type="password" name="pass1">
</td>
</tr>
<tr>
<td>
<font face=verdana size=1>herhaal wachtwoord:
</td>
<td>
<input type="password" name="pass2">
</td>
</tr>
<tr>
<td>
<input type="submit" value=registreer name="submit">
</td>
<td>
<input type="reset">
</td>
</tr>
</table>
</form>
<?php
}else{
//request everything
$dead = "false";//We make 'dead' if some fields are not filled in don't check for pass and name in db.
$message = "<font face=verdana size=1>vul alle velden goed in:<br>";
$username = $_POST['name'];
$pass1 = $_POST['pass1'];
$pass2 = $_POST['pass2'];
//begin search for errors
if(strlen($username) <= 1 or strlen($username) >=15){
$dead = "true";
$message .= "gebruikersnaam (2-14)<br>";
}
if(strlen($pass1) < 6 or strlen($pass1) > 20 or $pass1 !== $pass2) {
$dead = "true";
$message .= "wachtwoord (6-20) or de 2 wachtwoorden zijn niet het zelfde";
}
if($dead = "false"){
$username = strtolower(trim(strip_tags($username)));
$pass1 = trim($pass1);
$pass1 = md5($pass1);
$query = mysql_query("SELECT * FROM members WHERE username ='$username'");
$aantalrijen = mysql_num_rows($query);
if($aantalrijen == 1){
print "<font face=verdana size=1>Sorry, je grebruikers naam is al geregistreert.";
}
else{
$query1 = "INSERT INTO members(username, password) VALUES ('$username','$pass1')";
if(mysql_query($query1)){
print "<font face=verdana size=1>je bent succesvol geregistreert.";
}
}
}
elseif($dead == "true"){
print $message;
}
}
?>
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